7b^2+35b=0

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Solution for 7b^2+35b=0 equation: 



7b^2+35b=0

a = 7; b = 35; c = 0;
Δ = b2-4ac
Δ = 352-4·7·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$


$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-35}{2*7}=\frac{-70}{14}
=-5
$


$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+35}{2*7}=\frac{0}{14}
=0
$

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